Armstrong Number in C++ | Armstrong Number Program in C++

This article guide you for writing a Program in C++ which check whether the number is Armstrong number or not . Before going to write the C++ program to check whether the number is Armstrong number or not, let’s understand what is Armstrong number.

Armstrong number is a number that is equal to the sum of cubes of its digits. For example 0, 1, 153, 370, 371 and 407 are the Armstrong numbers.

Let’s try to understand why 371 is an Armstrong number.

407 = (4*4*4)+(7*7*7)+(0*0*0)    
where:    
(4*4*4)=64    
(7*7*7)=343    
(0*0*0)=0  
So:    
64+343+0=407   

Reverse Number Program in C++.

Let’s see the C++ program to check Armstrong Number.

    #include <iostream>  
    using namespace std;  
    int main()  
    {  
    int n,r,sum=0,temp;    
    cout<<"Enter the Number=  ";    
    cin>>n;    
    temp=n;    
    while(n>0)    
    {    
    r=n%10;    
    sum=sum+(r*r*r);    
    n=n/10;    
    }    
    if(temp==sum)    
    cout<<"Armstrong Number."<<endl;    
    else    
    cout<<"Not Armstrong Number."<<endl;   
    return 0;  
    }  

Output:

Enter the Number= 371
Armstrong Number.
Enter the Number= 342   
Not Armstrong Number.	
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Conclusion:

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